-Find the area of Mr. Gonzalez's classroom garden

Answer:
Step-by-step explanation:
We can find the area by breaking this into two rectangles one 3 by 7 and the other 1 by 2. The area of any rectangle is xy where x and y are its dimensions
A=3(7)+1(2)
A=21+2
A=23 yd^2
The area of Mr. Gonzalez's classroom garden is 23 square yd.
"The space occupied by two dimensional object."
In the rectangle ABDC,
AB = 3yd and BD = 5yd
Formula to find the area of classroom garden
Area of rectangle = length x width
Area of rectangle ABDC = AB x BD
= [tex]3[/tex] ×[tex]5[/tex]
[tex]= 15[/tex]square yd.
In the rectangle EFGC,
EF = 4yd and FG = 2yd
Area of rectangle EFGC = EF x GC
= [tex]4[/tex] × [tex]2[/tex]
= [tex]8[/tex] square yd.
Area of Mr. Gonzalez's classroom garden
= Area of rectangle ABDC + Area of rectangle EFGC
= [tex]15[/tex] + [tex]8[/tex]
= 23 square yd.
Hence, the area of Mr. Gonzalez's classroom garden is 23 square yd.
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