Answer :
lets calculate derivative of [tex] \sqrt{6x} [/tex]
That is:
[tex]( 6x^{ \frac{1}{2} } )' = 6* \frac{1}{2} * x^{ \frac{1}{2} -1 } = 3* x^{- \frac{1}{2} } [/tex]
Comparing that with offered answer we can see that results match.
That is:
[tex]( 6x^{ \frac{1}{2} } )' = 6* \frac{1}{2} * x^{ \frac{1}{2} -1 } = 3* x^{- \frac{1}{2} } [/tex]
Comparing that with offered answer we can see that results match.