Answer :
he equation is: y = Vo*t + (1/2)*a*t^2 50 m = (10 m/s)t + (1/2)(9.8 m/s^2)(t^2) then use the quadratic formula to solve fr t
Answer:
a)2.3s b)23m/s
Explanation:
a) According to the equation of motion S = ut+1/2at² where;
S is the distance or the height covered by the object. = 50m
u is the velocity of the object = 10m/s
a= +g(since the body is under a free fall, the acceleration due to gravity will be positive) = 10m/s²
Substituting this value in the formula to get the time we have;
50 = 10t + 1/2(10)t²
50 = 10t + 5t²
5t²+10t-50 = 0
Dividing through by 5 we have;
t²+2t-10 =0
Factorizing and using the general formula we have;
-2±√4+40/2
-2±√44/2
-2+√44/2
t = 2.3seconds
Therefore it takes the camera 2.3seconds to reach the ground.
b) velocity of the camera before it hits the ground can be gotten using the equation of motion
v = u+at
Since a = +g
v = u+gt... 1
The initial velocity of the camera will be zero at the point of drop, therefore its velocity before reaching the ground will be;
v = 0 +10(2.3)
v = 23m/s