Answer :
It's False!
If a=e and x=1, you'll get: [tex]ln(1)ln(e)=01=0 \neq -1=(−1)ln(e)=ln( e^{-1})=ln(\frac{1}{e} )[/tex]
If a=e and x=1, you'll get: [tex]ln(1)ln(e)=01=0 \neq -1=(−1)ln(e)=ln( e^{-1})=ln(\frac{1}{e} )[/tex]