Answer :
Since the function is a parabola, the maximum height would be the y-coordinate of the vertex. The x-coordinate of the vertex in standard parabolic form is
x = -b/2a.
In the problem, t would now be x.
t = -96/(2*-16) = 3*
Now that you have the time as 3 at the vertex, you can determine the height y at the vertex by substituting it in.
y = -16(3)^2 + 96(3) + 3
y = 147*
If they give you 122 feet and you need to find the time, then just plug that as y and solve for t.
122 = -16t^2 + 96t + 3
0 = -16t^2 + 96t - 119
t = 17/4, 7/4*
*Brainliest answer is always appreciated
x = -b/2a.
In the problem, t would now be x.
t = -96/(2*-16) = 3*
Now that you have the time as 3 at the vertex, you can determine the height y at the vertex by substituting it in.
y = -16(3)^2 + 96(3) + 3
y = 147*
If they give you 122 feet and you need to find the time, then just plug that as y and solve for t.
122 = -16t^2 + 96t + 3
0 = -16t^2 + 96t - 119
t = 17/4, 7/4*
*Brainliest answer is always appreciated