Answer :
4x^2 + 24x + 32 = 4(x^2 + 6x + 8)
6/2 = 3 so:
= 4( (x+3)^2 - 3^2 + 8 )
= 4( (x+3)^2 - 9 + 8)
= 4( (x+3)^2 - 1)
= 4(x+3)^2 - 4
vertex will be the minimum point, so: now,
4(x+3)^2 - 4 is at a minimum when x = -3 because it makes the stuff being squared equal to 0 so we know the x cord of vertex
is -3 the y cord is the constant on the end, -4
Hope this helps
6/2 = 3 so:
= 4( (x+3)^2 - 3^2 + 8 )
= 4( (x+3)^2 - 9 + 8)
= 4( (x+3)^2 - 1)
= 4(x+3)^2 - 4
vertex will be the minimum point, so: now,
4(x+3)^2 - 4 is at a minimum when x = -3 because it makes the stuff being squared equal to 0 so we know the x cord of vertex
is -3 the y cord is the constant on the end, -4
Hope this helps