Answer :
For question 1:
25°C = 298 K
ΔG = ΔH - T ΔS
ΔH= ΔG + TΔS = −91368 + (298)(−284)=−91368-84632=-175730
Therefore ΔH is approx - 176,000 J
For question 2:
The statement "A negative change in free energy, or −ΔG, represents a spontaneous reaction." is false
25°C = 298 K
ΔG = ΔH - T ΔS
ΔH= ΔG + TΔS = −91368 + (298)(−284)=−91368-84632=-175730
Therefore ΔH is approx - 176,000 J
For question 2:
The statement "A negative change in free energy, or −ΔG, represents a spontaneous reaction." is false
Answer:
For 1: The enthalpy change for the given reaction is -176000 J.
For 2: Yes, the negative sign of the gibbs free energy represents a spontaneous reaction.
Explanation:
- For 1:
For the given chemical reaction:
[tex]NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)[/tex]
We are given:
[tex]\Delta G[/tex] = Gibbs free energy = -91368 J
T = Temperature = [tex]25^oC=[273+25]K=298K[/tex]
[tex]\Delta S[/tex] = entropy of the reaction = -284 J/K
To calculate the enthalpy of the reaction, we use the equation for gibbs free energy, which is:
[tex]\Delta G=\Delta H-T\Delta S[/tex]
Putting values in above equation, we get:
[tex]-91368J=\Delta H-(298K)(-284J/K)\\\\\Delta H=-176000J[/tex]
Hence, the enthalpy change for the given reaction is -176000 J.
- For 2:
Gibbs free energy is defined as the energy which is available to do some work. It is represented as [tex]\Delta G[/tex]
Sign convention for [tex]\Delta G[/tex]
- If [tex]\Delta G[/tex] value comes out to be positive, it is considered as non-spontaneous reaction.
- If [tex]Delta G[/tex] value comes out to be negative, it is considered as spontaneous reaction.
So, yes the negative sign of the gibbs free energy represents a spontaneous reaction.