Answer :
The two possible solutions of the square of a number exceeds that number by 12 are: -3, and 4.
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X²=X+12
X²-X-12=0
(X-4)(X+3)=0
X-4=0 or X+3=0
Therefore, the answer is either 4 or -3
X²-X-12=0
(X-4)(X+3)=0
X-4=0 or X+3=0
Therefore, the answer is either 4 or -3