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Consider all three-digit numbers formed by using different digits from 0, 1, 2, 3 and 5. How many of these numbers are divisible by 6?

Answer :

4 numbers for the first term: 1, 2, 3, 5
5 numbers for the second term: 0,1,2,3,5
5 numbers for the third term: 0, 1, 2, 3, 5

100 combinations total, sooooooo

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