Answer :

theleangreenbean

Answer:

[tex]y=-\frac{1}{9}(x-2)^2-3[/tex]

Step-by-step explanation:

When a quadratic equation is in the form [tex]y=a(x-h)^2+k[/tex] (vertex form):

  1. The x-coordinate can be found by identifying which value makes [tex](x-h)^2[/tex] equal 0
  2. The y-coordinate can be found by identifying the k value (y=k)

Therefore, if the vertex of the function is at (2,-3), h needs to be 2 for [tex](x-h)^2[/tex]  to equal 0 and k needs to be -3. The only equation that displays this is G:

[tex]y=-\frac{1}{9}(x-2)^2-3[/tex]

I hope this helps!

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