Answer :
Answer:
[tex]\boxed {\boxed {\sf 4038.48 \ Joules}}[/tex]
Explanation:
Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:
[tex]q=mc\Delta T[/tex]
The substance's mass is 450.0 grams, the specific heat is 1.264 J/g°C, and the change in temperature is 7.1 °C.
[tex]m= 450.0 \ g \\c= 1.264 \ J/g \textdegree C\\\Delta T= 7.1 \ \textdegree C[/tex]
Substitute the values into the formula.
[tex]q= (450.0 \ g)(1.264 \ J/g \textdegree C)(7.1 \ \textdegree C)[/tex]
Multiply the first 2 values together. The grams will cancel out.
[tex]q= 568.8 \ J/ \textdegree C (7.1 \ \textdegree C)[/tex]
Multiply again. This time, the degrees Celsius cancel out.
[tex]q= 4038.48 \ J[/tex]
4038.48 Joules of heat energy are released.