Answer :
Answer:
[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to use the 1:2 mole ratio of nitrogen to ammonia to calculate the moles of the latter that are produced when reacting 3.15 moles of the former with hydrogen as shown below:
[tex]n_{NH_3}^{produced}=3.15molN_2*\frac{2molNH_3}{1molN_2}[/tex]
Thus, by solving the equation we obtain:
[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]
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