Answered

How much of a radioactive kind of niobium will be left after 105 days if you start with 3,920 grams and the half-life is 35 days?

Answer :

Cricetus

Answer:

"490 grams" would be the correct solution.

Step-by-step explanation:

The given values are:

Half time,

T = 35 days

Total time,

t = 105 days

As we know,

⇒ [tex]A=A_o(\frac{1}{2} )^{\frac{t}{T} }[/tex]

On substituting the values, we get

⇒     [tex]=3920\times (\frac{1}{2})^{\frac{105}{35} }[/tex]

⇒     [tex]=3920\times (0.5)^3[/tex]

⇒     [tex]=3920\times 0.125[/tex]

⇒     [tex]=490 \ grams[/tex]

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