Answer :

jvitasoy

Answer:

[tex]x_{1}[/tex]=(3+[tex]\sqrt{5}[/tex])/2

[tex]x_{2}[/tex]=(3-[tex]\sqrt{5}[/tex])/2

Step-by-step explanation:

x^2-3x+1=0

[tex]x_{1}[/tex]=(3+[tex]\sqrt{3^2-4*1*1}[/tex])/2=(3+[tex]\sqrt{5}[/tex])/2

[tex]x_{2}[/tex]=(3-[tex]\sqrt{3^2-4*1*1}[/tex])/2=(3-[tex]\sqrt{5}[/tex])/2

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