Answer :
Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / [tex]\sqrt{n*0.2*0.8}[/tex] ~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of n take the positive number
