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Carter is creating quilt pieces in the shape of a kite as shown below. One of the kite diagonals measures 6 inches, and the area of each piece must be between 20 and 25 square inches.

Answer :

MrRoyal

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]d_1 =6in[/tex] --- the first diagonal

[tex]Area = (20in^2,25in^2)[/tex]

The question is incomplete, as the image of the kite and what is required are not given

However, a possible question could be to calculate the length of the other diagonal

Calculating the length of the other diagonal, we have:

[tex]Area = 0.5 * d_1 * d_2[/tex]

Make d2 the subject

[tex]d_2 = \frac{Area }{0.5 * d_1}[/tex]

Multiply by 2/2

[tex]d_2 = \frac{2 * Area }{2* 0.5 * d_1}[/tex]

[tex]d_2 = \frac{2 * Area }{1 * d_1}[/tex]

[tex]d_2 = \frac{2 * Area }{d_1}[/tex]

When Area = 20, we have:

[tex]d_2 = \frac{2 * 20}{6}[/tex]

[tex]d_2 = \frac{40}{6}[/tex]

[tex]d_2 = 6.67[/tex]

When Area = 25, we have:

[tex]d_2 = \frac{2 * 25}{6}[/tex]

[tex]d_2 = \frac{50}{6}[/tex]

[tex]d_2 = 8.33[/tex]

So:

[tex]d_2 = (6.67,8.33)[/tex]

This means that the length of the other diagonal is between 6.67in and 8.33in

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