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An electron acquires 7.45 x 10 ^-16 J of kinetic energy when it is accelerated by an electric field from plate A to plate B. What is the potential difference between the plates, and which plate is at the higher potential?

Answer :

Answer: Kinetic energy of electron = 7.45 x 10^-16 J We know that Potential difference = Work done per unit charge = Kinetic energy of electron / ( 1.6 x 10^-19 ) = (7.45 x 10^-16) / ( 1.6 x 10^-19) = 4656.25 V

Explanation:

The potential difference between the plates is [tex]4650.43V[/tex]

The Potential difference is also defined as the work done per unit charge.

Work done = kinetic energy = [tex]7.45*10^{-16}J[/tex]

Charge on one electron = [tex]1.602*10^{-19}C[/tex]

Potential difference,

                         [tex]V=\frac{7.45*10^{-16}}{1.602*10^{-19} }=4650.43Volt[/tex]

Hence, the potential difference between the plates is [tex]4650.43V[/tex]

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