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Using a horizontal force of 60 N, a wagon is pushed horizontally across the floor a distance of 12 meters at a constant speed of 2.3 m/s
a) What is the work done by the force?
b) What is the power supplied by the force?

Answer :

xero099

Answer:

a) The work done by the force is 720 joules, b) The power supplied by the force is 138 watts.

Explanation:

a) Since force is uniform and parallel to the direction of motion, the work ([tex]W[/tex]), in joules, done by the force ([tex]F[/tex]), in newtons, is defined by this formula:

[tex]W = F\cdot s[/tex] (1)

Where [tex]s[/tex] is the travelled distance, in meters.

If we know that [tex]F = 60\,N[/tex] and [tex]s = 12\,m[/tex], then the work done by the force is:

[tex]W = F\cdot s[/tex]

[tex]W = (60\,N)\cdot (12\,m)[/tex]

[tex]W = 720\,J[/tex]

The work done by the force is 720 joules.

b) And an expression for the power supplied by the force ([tex]\dot W[/tex]), in watts, is concieved by differentiating (1) in time:

[tex]\dot W = F\cdot \dot s[/tex]

Where [tex]\dot s[/tex] is the speed of the wagon, in meters per second.

If we know that [tex]F = 60\,N[/tex] and [tex]\dot s = 2.3\,\frac{m}{s}[/tex], then the power supplied by the force is:

[tex]\dot W = F\cdot \dot s[/tex]

[tex]\dot W = (60\,N)\cdot \left(2.3\,\frac{m}{s} \right)[/tex]

[tex]\dot W = 138\,W[/tex]

The power supplied by the force is 138 watts.

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