dylash2007
Answered

I’ll give the Brainliest to who answers these questions with reasonable explanations.



1. A bag has 16 marbles in it: 6 red, 4 blue, 3 yellow, and 3 green. A marble is drawn and put back, and then another marble is drawn. What is the probability that a blue marble was drawn followed by a yellow marble?




2. A bag has 16 marbles in it: 6 red, 4 blue, 3 yellow, and 3 green. A marble is drawn and not put back, and then another marble is drawn. What is the probability that a blue marble was drawn followed by a yellow marble?


Thank you.

Answer :

DragonPup315

Answer:

1. 0.0469 (4.d.p)

2. 0.05

Step-by-step explanation:

1. First we'll find the probability of drawing a blue marble.

P = (No. favourable events)/(Total events)

In this case it's:

P = (No. blue marbles)/(Total Marbles)

Therefore P(Blue) = 4/16 = 0.25

Now we find the probability of drawing a yellow marble:

The total number will be the same because the blue marble will have been put back.

P(Yellow) = 3/16 = 0.1875

Now, since we are calculating the probability of both happening we multiply together the two individual probabilities to get the combined probability of both:

0.25 x 0.1875 = 0.0469 (4.d.p)

2. The probability of drawing a blue marble is still the same so we can keep that: P(Blue) = 0.25

But this time, the marble is not replaced. This means that the total number of marbles has changed when drawing the yellow marble:

P(Yellow) = 3/15 = 0.2

Now we multiply them together again to find the combined probability of both happening:

0.25 x 0.2 = 0.05

Hope this helped!

Other Questions