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The sum of two numbers is 40. The difference of those numbers is 8. Write a
system of equations and solve to find both numbers.

Answer :

st991113

Answer:

let two number be x and why

in 1st condition

x+y=40

x=40-y eqn (i)

in 2nd condition

x-y=8

x=8+y eqn (ii

now from eqn (i) and (ii)

40-y=8+y

32=2y

y=16

now putting the vale of why in eqn (i)

we get

x=40-16

=24

so two number are 24 and 16

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