Answer :

pc192y

Answer:

{x | x ∈ R, 4,-1}

Step-by-step explanation:

[tex]y=x^2-3x-4[/tex]

[tex]y=x^2+x-4x-4[/tex]

[tex]y=(x^2+x)+(-4x-4)[/tex]

[tex]y=x(x+1)+(-4)(x+1)[/tex] Distributive property

[tex]y=(x+(-4))(x+1)[/tex] Distributive Property

[tex]y=(x-4)(x+1)[/tex]

set y to 0

[tex]0=(x-4)(x+1)[/tex]

set the factors to 0

[tex]0=x-4; 0=x+1[/tex]

[tex]4=x; -1=x[/tex]

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