Answer:
[tex] \approx \: 198.1 \: {cm}^{2} [/tex]
Step-by-step explanation:
Given figure consists of a parallelogram and two semicircles with diameters 14 cm and 8 cm
(Opposite sides of a parallelogram are equal in measure and they are the diameters of the semicircles)
Therefore,
Area of the figure = Area of the parallelogram with base 8 cm and height 12 cm + Area of semicircle with radius (14/2 = 7) 7 cm + Area of the semicircle with radius (8/2 =4) 4 cm
[tex] = b \times h + \frac{1}{2} \times \pi {(7)}^{2} + \frac{1}{2} \times \pi {(4)}^{2} \\ \\ = 8 \times 12 + \frac{1}{2} \pi(49 + 16) \\ \\ = 96 + \frac{1}{2} \times 3.14 \times 65 \\ \\ = 96 + 102.05 \\ \\ = 198.05 \\ \\ \approx \: 198.1 \: {cm}^{2} [/tex]
