Answer :

Answer:

[tex]x^{2} -16x +64 = 0[/tex]

Step-by-step explanation:

[tex](x-8)^{2}[/tex] is the same as saying [tex](x-8)(x-8)[/tex]

therefore, you use FOIL(first outside inside last) to get

[tex]x^{2} -8x-8x+64[/tex]

which is [tex]x^{2} -16x +64 = 0[/tex] in standard form

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