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Answered

When finding the 9th term in a geometric sequence with a common ratio of 2 and a first
term of 3;
which is the value of (n-1)?

Answer :

Hrishii

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

[tex] t_n = a r^{(n-1)}[/tex] ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

[tex] t_9 = (3) (2)^{9-1}[/tex]

[tex] t_9 = (3) (2)^{8}[/tex]... (2)

Comparing equations (1) & (2), we obtan:

(n - 1) = 8

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