Answer :
We multiply both equations by a constant term so that when we subtract the equations, the y values cancel out:
4(4x - 3y = 3)
3(5x - 4y = 3)
16x - 12y = 12
15x -12y = 9; subtracting the second equation from the first:
x = 3
4(4x - 3y = 3)
3(5x - 4y = 3)
16x - 12y = 12
15x -12y = 9; subtracting the second equation from the first:
x = 3