Answer :

bcalle
(c - 3)(2c - 1) is the factored form
nobrains
[tex]2c^2-7c+3[/tex]

You need 2 numbers that when added together equal the coefficient of c (-7 in this case), and when multiplied equal the product of the constant and coefficient of c^2 (this product is 2*3 = 6).
Two numbers that add to -7 and multiply to 6 are -6 and -1.

The middle term -7c becomes -6c - 1c.
[tex]2c^2-6c-1c+3 \\ 2c(c-3) -1(c-3) \\ (c-3)(2c-1)[/tex]

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