Answer :
angular magnifiction=[tex]m= \frac{ f_{0} }{ f_{e} } [/tex]
[tex] f_{0}= [/tex]=focal length of object lens=20m
[tex] f_{e}= [/tex]focal length of eye lens=1.90 m
so magnification=m=20/1.9=?
[tex] f_{0}= [/tex]=focal length of object lens=20m
[tex] f_{e}= [/tex]focal length of eye lens=1.90 m
so magnification=m=20/1.9=?
Magnification = (focal length of the objective) / (focal length of the eyepiece)
= (20.0 m) / (1.9 cm)
= (2,000 cm) / (1.9 cm)
= 1,053 (rounded)