Answer :
Formula for solving (finding x intercepts) quadratic equation is:
[tex]x = \frac{-b +- \sqrt{b^2 - 4ac} }{2a} [/tex]
Quadriatic equation we can write as:
ax^2 + bx + c = 0
comparing this with given equation we can see that:
a = 1
b = -2
c = -3
if we express this in formula for solving equation we get
[tex]x = \frac{-(-2) +- \sqrt{(-2)^2 - 4*1*(-3)} }{2*1} [/tex]
[tex]x = \frac{-b +- \sqrt{b^2 - 4ac} }{2a} [/tex]
Quadriatic equation we can write as:
ax^2 + bx + c = 0
comparing this with given equation we can see that:
a = 1
b = -2
c = -3
if we express this in formula for solving equation we get
[tex]x = \frac{-(-2) +- \sqrt{(-2)^2 - 4*1*(-3)} }{2*1} [/tex]
Answer:
A. Is The Answer
Step-by-step explanation:
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