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Consider the trinomial 9x2 + 21x + 10. What value is placed on top of the X? What value is placed on the bottom of the X? What is the factored form of 9x2 + 21x + 10?

Answer :

1: 90
2: 21
3: (3x+2)(3x+5)

Answer: 1) Value is placed on top of the X =90

2) Value is placed on the bottom of the X =21

3)  Factored form will be (3x+5)(3x+2)

Step-by-step explanation:

Since we have given that

[tex]9x^2 + 21x + 10[/tex]

As we know the quadratic form :

[tex]ax^2+bx+c=0[/tex]

1) Value is placed on top of the X is given by

[tex]a\times c=9\times 10=90[/tex]

2) Value is placed on the bottom of the X is given by

[tex]b=21[/tex]

3) Factorised form:

We will use "Split the middle term":

[tex]9x^2 + 21x + 10\\\\=9x^2+15x+6x+10\\\\=3x(3x+5)+2(3x+5)\\\\=(3x+2)(3x+5)[/tex]

Hence, Factored form will be

(3x+5)(3x+2)

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