Answer :
Answer:
[tex]3x+7[/tex]
Step-by-step explanation:
[tex]\frac{3x^2-14x-49}{x-7}[/tex]
before dividing this fraction , lets factor the numerator
[tex]3x^2-14x-49[/tex]
Product is -49 and sum is -14, lets break the middle term using factors
[tex](3x^2+7x)+ (-21x-49)[/tex]
Take out GCF from each group
[tex]x(3x+7)-7(3x+7)[/tex]
[tex](3x+7)(x-7)[/tex]
Now we replace the factors in the numerator
[tex]\frac{(3x+7)(x-7)}{x-7}[/tex]
We have (x-7) at the top and bottom , so we cancel it out
[tex]3x+7[/tex]