Answer :

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

  • [tex] \tt \: \frac { x - 3 } { 4 } = \frac { r } { 4 } \\ [/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

  • We'll have 2 solutions because this question is in 2 variables (x & r) & we need to solve for both of them.

First, let's solve for 'r'.

[tex] \tt\frac { x - 3 } { 4 } = \frac { r } { 4 } \\ [/tex]

Multiply both sides of the equation by 4.

[tex] \tt \: x-3=r [/tex]

Swap sides so that all variable terms are on the left-hand side.

[tex] \boxed{\boxed{ \bf \: r=x-3 }}[/tex]

_________________

Now, let's solve for 'x'.

[tex] \tt \: \frac { x - 3 } { 4 } = \frac { r } { 4 } \\ [/tex]

Multiply both sides of the equation by 4.

[tex] \tt \: x-3=r [/tex]

Add 3 to both sides.

[tex] \boxed{ \boxed{ \bf \: x=r+3 }}[/tex]

[tex]\\ \rm\longmapsto \dfrac{x-3}{4}=\dfrac{x}{2}[/tex]

[tex]\\ \rm\longmapsto 2(x-3)=4x[/tex]

[tex]\\ \rm\longmapsto x-3=\dfrac{4x}{2}[/tex]

[tex]\\ \rm\longmapsto x-3=2x[/tex]

[tex]\\ \rm\longmapsto x-2x=3[/tex]

[tex]\\ \rm\longmapsto -x=3[/tex]

[tex]\\ \sf\longmapsto x=-3[/tex]

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