Answer :
Answer:
[tex]\int\limits^ {-1} \, (x) = 9x +18[/tex]
Step-by-step explanation:
We must find the inverse of the following function:
[tex]\int\limits {x} =[/tex] [tex]\frac{1}{9}x - 2[/tex]
to solve this, you change f(x) by y
y= [tex]\frac{1}{9} x - 2[/tex]
exchange the variables:
[tex]x\frac{1}{9}y - 2[/tex]
You clear the variable "y"
[tex]x+ 2 = \frac{1}{9}y[/tex]
9(x+2) = y
y = 9(x+2)
y = 9x +18
finally you change "y" to f ^-1 (x) =
f^-1 (x) = 9x+18