Two football players move in a straight line directly toward one another. Their equations of motion are as follows:
x1 = 0.1 m + (–3.9 m/s )t

x2 = –6.3 m + (2.8 m/s )t

At what time do the players collide?

Answer :

The time when the two players will collide is 0.96 s.

The equation of motion of the two players is given as;

x1 = 0.1 m + (–3.9 m/s )t

x2 = –6.3 m + (2.8 m/s )t

The time when the two players collide, their displacement is equal or the difference in their position will be zero.

[tex]X_1 - X_2 = 0\\\\0.1 - 3.9 t - (-6.3 + 2.8t) = 0\\\\0.1 -3.9t + 6.3 -2.8t = 0\\\\6.4 -6.7t = 0\\\\6.7t = 6.4\\\\t = \frac{6.4}{6.7} = 0.96 \ s[/tex]

Thus, the time when the two players will collide is 0.96 s.

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