Answer :

Values of x and y will be 12 and 5 respectively.

It's given in the question,

  • Three points Q, R and S are collinear.
  • Coordinates of Q → (2, 0)
  • Coordinates of R → (8, 3)
  • Coordinates of S → (x, y)
  • QR : RS = 3 : 2

Since, expression for the coordinates of a point (h, k) which divides the segment joining points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] in the ratio of m : n is given by,

h = [tex]\frac{mx_2+nx_1}{m+n}[/tex]

k = [tex]\frac{my_2+my_1}{m+n}[/tex]

Since, R is a point on segment QS dividing in the ratio of 3 : 2, coordinates of R will be,

[tex]8=\frac{3x+2\times 2}{3+2}[/tex]

[tex]8=\frac{3x+4}{5}[/tex]

[tex]3x+4=40[/tex]

[tex]3x=36[/tex]

[tex]x=12[/tex]

Similarly, [tex]3=\frac{3y+2\times 0}{3+2}[/tex]

[tex]3=\frac{3y}{5}[/tex]

[tex]3y=15[/tex]

[tex]y=5[/tex]

       Therefore, values of x and y will be 12 and 5 respectively.

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