Answer :
h₁(x)=(x+8-3)³-5=(x+5)³-5 is the function h(x) 3 units right
h₂(x)=(x+8)³-5+3=(x+8)³-2 is the funtion h(x) 3 units up
h₃(x)=(x+8-3)³-5+3=(x+5)³-2 is the funtion h(x) 3 unist right and 3 units up.
answer: the new funtion will be: h(x)=(x+5)³-2
h₂(x)=(x+8)³-5+3=(x+8)³-2 is the funtion h(x) 3 units up
h₃(x)=(x+8-3)³-5+3=(x+5)³-2 is the funtion h(x) 3 unist right and 3 units up.
answer: the new funtion will be: h(x)=(x+5)³-2