Answer:
• From trigonometric ratios:
[tex]{ \rm{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\ [/tex]
→ theta is 41°
→ opposite is y
→ hypotenuse is 26 ft
[tex]{ \tt{ \sin(41) = \frac{y}{26} }} \\ \\ { \tt{y = 26 \sin(41) }} \\ \\ { \boxed{ \tt{ \: y = 17.06 \: \: ft}}}[/tex]
