Assuming the pattern continues...
Answer:
[tex]128[/tex]
Step-by-step explanation:
We see that this is a geometric series with common ratio [tex]-2[/tex].
So, the 6th term is the 4th term times [tex](-2)^2=2^2=4[/tex].
So, the answer is [tex]4(-32)=\boxed{128}[/tex] and we're done!
Note:
The closed form for this geometric series is [tex]4*(-2)^{n-1}[/tex], which means the nth term is always [tex]4*(-2)^{n-1}[/tex].
