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An 8.0g bullet is fired horizontally into a 9kg block of wood on a frictionless table and is embedded in it. After the collis6, the block and the bullet slide ,along the surface together with a speed of 10cm/s.

A. find the initial speed


b.find the kinetic energy of the system before collision


c.find the kinetic energy of the system after collision

d. what percentage of the systems original kinetic energy was lost


please help if you can.

Answer :

dxdph4pi
A. 8.0g*v = (8.0g+9kg)*10cm/s
0.008kg*v=0.9008kgm/s
v=112.6m/s
b. K=0.5*0.008kg*(112.6m/s)^2=50.71504J
c. K=0.5*9.008kg*(0.1m/s)^2=0.04504J
d. 99.999111900532859680284191829485%

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