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Is each given binomial a factor of the given polynomial? If so, write the polynomial as a product of two factors.Polynomial: P(x) = 8x^3 - 10x^2 + 28x - 16;
Binomial: x - 3

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devishri1977

Answer:

Step-by-step explanation:

p(x)  = 8x³ - 10x² + 28x - 16

p(3) = 8*3³ - 10*3² + 28*3 - 16

      = 8*27 - 10*9 + 84 - 16

      = 216 - 90 + 84 - 16

     = 194.

There is remainder. So (x- 3 ) is not a factor of the given polynomial p(x)

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