In the following reaction, how many liters of oxygen will react with 270 liters of ethene (C2H4) at STP?
C2H4(g) + 3O2(g) 2CO2(g) + 2H2O(g)
The volume of one mole of gas at STP is 22.4 liters.

Answer :

According to the equation you have 1 mole of C2H4 and 3 moles of O2.

1 • (22.4L / 270L) = 3 • (22.4L / x)

1/270L = 3/x

x = 3(270) / 1

x = 810 L

810 Liters of oxygen will react with 270 liters of ethene (C2H4) at STP

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