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The enthalpy of combustion for octane (C8H18(l)), a key component of gasoline, is –5074 kJ/mol. The reaction equation is: C8H18(l) + 12.5O2(g) arrwo 8CO2(g) + 9H2O(g).
What is the enthalpy of formation for this reaction?
16CO2(g) + 18H2O(g) arrow 2C8H18(l) + 25O2(g)

Answer :

The enthalpy change for reaction (2) is 10178 kJ/mol.

What is enthalpy of reaction?

The term enthalpy of reaction has to do with the heat that is evolved or absobed in a chemical reaction.

We have the equations;

  1. C8H18(l) + 12.5O2(g) -----> 8CO2(g) + 9H2O(g).
  2. 16CO2(g) + 18H2O(g) ----->2C8H18(l) + 25O2(g)

We can see that equation (2) is obtained from (1) by multiplication using a factor of 2. and also (2) is a reverse of (1). It then follows that the enthalpy change for reaction (2) is 10178 kJ/mol.

Learn more about enthalpy: https://brainly.com/question/15289741?

Answer:

10,148 kJ

Explanation:

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