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What is the equation of the line that passes through the point (−3,0) and has a slope of -1/3

Answer :

Answer:

(-3,0)=(x1,y1)

slope=m=-1/3

the equation of the line is

y-y1=m(x-x1)

y-0=1/3(x-(-3))

y   =1/3(x+3)                                        (-- is + at right side)

y   =1/3*x + 1/3*3

y   =1/3 x   +1                                        (3 has been canceled from the right side)

Step-by-step explanation:

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