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Two 2.5 kg bowling balls are 0.50 m apart. What is the force of gravity of the first bowling ball due to the
second? Compare this to the force of gravity on the second bowling ball due to the first.

Two 2.5 kg bowling balls are 0.50 m apart. What is the force of gravity of the first bowling ball due to the second? Compare this to the force of gravity on the class=

Answer :

Answer:The answer is A

Explanation:

To determine the force, we use the equation

Fg= G m1 m2/r2

, where Fg is the force of gravity, G is the gravitational constant,

m1

is the mass of the first body,

m2

is the mass of the second body, and r is the radius. Hence, we have

Fg=6.67×10−11 N×m2/kg2×2.5 kg×2.5 kg/(0.50 m)2=1.7×10−9N

. Since this is a gravitational problem, the force on one body has the same force as the other body, but the directions are opposite.

Answer:

The answer is A have a good day!

Explanation:

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