Answer :
To factor this:
1st: take out GCF
3(2x^2 - x - 3)
2nd: do AC method by starting with what 2 numbers equal -6 [ac] and add up to be -1 [b]
Two numbers: -3, 2
3rd: split b into these two numbers
3( 2x^2 + 2x - 3x - 3)
4th: group the first two and last two terms and take out their GCF's
3( 2x[ x+ 1 ] -3 [x+1] )
5th: finish up
3( 2x - 3)( x + 1 )
Jamal factored it completely because he took out the GCF in the first step while Jennifer did not.
1st: take out GCF
3(2x^2 - x - 3)
2nd: do AC method by starting with what 2 numbers equal -6 [ac] and add up to be -1 [b]
Two numbers: -3, 2
3rd: split b into these two numbers
3( 2x^2 + 2x - 3x - 3)
4th: group the first two and last two terms and take out their GCF's
3( 2x[ x+ 1 ] -3 [x+1] )
5th: finish up
3( 2x - 3)( x + 1 )
Jamal factored it completely because he took out the GCF in the first step while Jennifer did not.