Answer :
If we were to use the sine law we would get
sin(B) / b = sin(A) / a ----> sin(B) = b*sin(A)/a = 13*sin(35)/6 = 1.24275 to 5 d.p..,
so since this is greater than 1 there can be 0 triangles with these dimensions,
as the range of the sine function is [-1,1].
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
sin(B) / b = sin(A) / a ----> sin(B) = b*sin(A)/a = 13*sin(35)/6 = 1.24275 to 5 d.p..,
so since this is greater than 1 there can be 0 triangles with these dimensions,
as the range of the sine function is [-1,1].
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.