Solve the equations
1) 4x=-36
A. 9
B. -9
C. -40
D. 40

2) 5x-15=50
A. 13
B. -13
C. -7
D. 7

3) 4(x+2)-17=35
A. -11
B. 25/2
C. 15
D. 11

4) 6x+12=4x-18
A. -15
B. 15
C. -3
D. 3

5) 1/2(4x-10)+5=x-11
A. 11
B. 6
C. -11
D. -6

Answer :

Answer:

(1)The value of x is -9 .

Option (B) is correct .

(2)The value of x is 13 .

Option (A) is correct .

(3)The value of the x is 11 .

Option (D) is correct .

(4) The value of the x is -15 .

Option (A) is correct .

(5)The value of the x is -11 .

Option (C) is correct .

Step-by-step explanation:

First Part

As given

4x = -36

[tex]x = \frac{-36}{4}[/tex]

x = -9

Therefore the value of x is -9 .

Option (B) is correct .

Second Part

As given

5x - 15 = 50

5x = 50 + 15gg

5x = 65

[tex]x = \frac{65}{5}[/tex]

x = 13

Therefore the value of x is 13 .

Option (A) is correct .

As given

4(x+2)-17=35

4x + 8 - 17 = 35

4x = 35 + 17 - 8

4x = 44

[tex]x = \frac{44}{4}[/tex]

x = 11

Therefore the value of the x is 11 .

Option (D) is correct .

Fourth Part

As given

6x+12=4x-18

6x-4x = -12-18

2x = -30

[tex]x = \frac{-30}{2}[/tex]

x = -15

Therefore the value of the x is -15 .

Option (A) is correct .

Fifth Part

As given

[tex]\frac{1}{2}(4x-10)+5=x-11[/tex]

Simplify the above

4x-10+5×2 = 2x-22

4x-10+10= 2x-22

4x-2x = -22

2x=-22

[tex]x = \frac{-22}{2}[/tex]

x = -11

Therefore the value of the x is -11 .

Option (C) is correct .

1. The value of x is [tex]\boxed{x =  - 9}.[/tex] Option (B) is correct.

2. The value of x is [tex]\boxed{x = 13}[/tex]. Option (A) is correct.

3. The value of x is [tex]\boxed{x = 11}[/tex]. Option (D) is correct.

4. The value of x is [tex]\boxed{x = - 15}[/tex]. Option (A) is correct.

5. The value of x is [tex]\boxed{x = - 11}[/tex]. Option (C) is correct.

Further explanation:

Always use the PEDMAS rule to solve the grouping of multiplication, addition, subtraction and division.

Here, P is parenthesis, E is exponents, M is multiplication, D is division, A is addition and S is subtraction.

Explanation:

Part (1)

The given equation is [tex]4x =  - 36[/tex]

Solve the above expression to obtain the value of x.

[tex]\begin{aligned}4x &= - 36\\\frac{{4x}}{4}&= \frac{{ - 36}}{4}\\x&= - 9\\\end{aligned}[/tex]

The value of [tex]x[/tex] is [tex]\boxed{x =  - 9}.[/tex]

Part (2)

The equation is [tex]5x - 15 = 50.[/tex]

Solve the above expression to obtain the value of x.

[tex]\begin{aligned}5x - 15 &= 50\\5x &= 65\\x&= \frac{{65}}{5}\\x&= 13\\\end{aligned}[/tex]

The value of [tex]x[/tex] is [tex]\boxed{x = 13}.[/tex]

Part (3)

The equation is [tex]4\left( {x + 2} \right) - 17 = 35.[/tex]

Solve the above expression to obtain the value of x.

[tex]\begin{aligned}4\left( {x + 2} \right) - 17 &= 35\\4x + 8 &= 35 + 17 \\4x &= 52- 8\\4x &= 44\\x &= 11\\\end{aligned}[/tex]

The value of [tex]x[/tex] is [tex]\boxed{x = 11}.[/tex]

Part (4)

The equation is [tex]6x + 12 = 4x - 18.[/tex]

Solve the above expression to obtain the value of x.

[tex]\begin{aligned}6x + 12 &= 4x - 18\\6x - 4x &=  - 18 - 12\\2x &= - 30\\x &= \frac{{ - 30}}{2}\\x &=- 15\\\end{aligned}[/tex]

The value of [tex]x[/tex] is [tex]\boxed{x = - 15}.[/tex]

Part (5)

The equation is [tex]\dfrac{1}{2}\left( {4x - 10} \right) + 5 = x - 11[/tex]

Solve the above expression to obtain the value of x.

[tex]\begin{aligned}\frac{1}{2}\left( {4x - 10} \right) + 5 &= x - 11\\\frac{1}{2}\left( {4x - 10} \right) &= x - 11 - 5\\\left( {4x - 10} \right) &= 2\left( {x - 16} \right)\\4x - 10 &= 2x - 32\\4x - 2x &= - 32 + 10\\2x &= - 22\\x&= - 11\\\end{aligned}[/tex]

The value of [tex]x[/tex] is [tex]\boxed{x = - 11}.[/tex]

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Answer details:

Grade: High school

Subject: Mathematics

Chapter: Number system

Keywords: factor, factorization, 4x = -36, 5x-15=50, 4(x+2)-17=35, equation, value of x, division, multiplication, subtraction, solve the equation, solution, linear equation, line

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