(x,y) or
(x,f(x))
so just plug the first value in and see if yo get the 2nd value
A. when x=-2, then is f(x)=48?
remember, x^-m=1/(x^m)
3(1/4)^-2=3/((1/4)^2)=3/(1/16)=3*16=48
true
B. x^0=1
so 3(1/4)^0=3(1)=3
true
C. when x=2
3(1/4)^2, 3(1/16), 3/16
true
D. 12
das is obviously false but anyway
3(1/4)^12=3(1/big number)=3/big number=small number but not zero
answer is A,B,C
