Answer :

nobrains
You can substitute in values of x into the given equation y = 4x^2 - 1 and determine their corresponding y values. Then see which of these points correspond to the graphs q, r, s, t.

For example, if x = 0, then
y = 4(0)^2 - 1
y = -1
The point would be (0, -1)

If x = 1, then
y = 4(1)^2 - 1
y = 4 - 1
y = 3
The point would be (1, 3)

The only graph with points (0, -1) and (1, 3) is graph t.

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