Answered

Write the equation of a line that is perpendicular to the given line and that passes through the given point 2x+9y=-30;(-8,0)

Answer :

y=(-30-2x)/9 the slop is -2/9 because perpendicular to the given line so the new slop is 9/2
y=9/2x+b
0=9/2*-8+b
0=-36+b
b=36
y=9/2x+36 is the answer

Answer:

[tex]y=\frac{9}{2}x+36[/tex]

Step-by-step explanation:

The given equation is 2x+9y=-30.

Subtracting 2x both sides :

9y=-2x-30

Dividing both sides by 9 we have:

[tex]y=\frac{-2}{9}x -\frac{10}{3}[/tex]

This equation is of the form y=mx+b where the slope m=[tex]\frac{-2}{9}[/tex]

Slope of a perpendicular line =[tex]\frac{9}{2}[/tex]

The perpendicular line passes through the point (-8,0)

The equation of the perpendicular line is :[tex]y-0=\frac{9}{2} (x+8)[/tex]

Or [tex]y=\frac{9}{2}x+36[/tex]

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