let the length of side of the square be a
by the Pythagoras theorem a^2 + b ^2 = c^2
taking b=a, a^2 + a^2 =2a^2
= a[tex] \sqrt{2} [/tex]
a[tex] \sqrt{2} [/tex]= 8
2a^2 = 64
a^2 = 32
a = [tex] \sqrt{32} [/tex]
a = 4[tex] \sqrt{2} [/tex]
let the length of side of the square be a
by the Pythagoras theorem a^2 + b ^2 = c^2
taking b=a, a^2 + a^2 =2a^2
= a
a= 8
2a^2 = 64
a^2 = 32
a =
a = 4